用户提问: 5550"XOR(555*if(now()=sysdate(),sleep(15),0))XOR"Z
Ai回答: This is a time-based blind SQL injection payload designed to exploit a vulnerable database query. Let's break it down:
Payload Analysis:
```sql
5550"XOR(555*if(now()=sysdate(),sleep(15),0))XOR"Z
```
- Structure: Attempts to break out of a quoted string (`"`) and inject malicious logic.
- XOR Logic: Uses `XOR` to create a conditional statement (if the first part is false, the second part executes).
- Time-Based Attack:
- `if(now()=sysdate(),sleep(15),0)` forces the database to sleep for 15 seconds if the condition is true (which it always is).
- This delay confirms SQL injection vulnerability.
How It Works:
1. The attacker inputs this payload into a vulnerable field (e.g., login form, search box).
2. If the application concatenates inputs directly into a SQL query without sanitization, the database executes the `sleep(15)` command.
3. A 15-second delay in the response confirms the injection worked.
Vulnerable Code Example (PHP/MySQL):
```php
$id = $_GET['id']; // User-controlled input
$query = "SELECT * FROM users WHERE id = \"$id\""; // Unsafe concatenation
```
If `$id` is your payload, the query becomes:
```sql
SELECT * FROM users WHERE id = "5550" XOR (555*if(now()=sysdate(),sleep(15),0)) XOR "Z"
```
Mitigation:
1. Use Prepared Statements (Parameterized Queries):
```php
$stmt = $pdo->prepare("SELECT * FROM users WHERE id = ?");
$stmt->execute([$id]);
```
2. Input Validation: Reject unexpected characters (e.g., quotes, SQL keywords).
3. WAF Rules: Block known SQLi patterns (e.g., `sleep()`, `XOR` in inputs).
Ethical Note:
- Only test systems you own or have permission to assess.
- Unauthorized testing is illegal.
Need help securing an application or crafting a safe test? Let me know your context!
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提问时间: 2025-07-10 01:18:47
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